Give any iterable object capability to use .one(), .one_or_none(), .many(k), .skip(k), .all() API.
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iterproxy
DocumentationYou may seen the following code style in many ORM framework, this pattern provides a user friendly API to access items from the iterator object:
.. code-block:: python
query(...).one()
query(...).one_or_none()
query(...).many(3)
query(...).all(5)
query(...).skip(5).many(3)
iterproxy <https://github.com/MacHu-GWU/iterproxy-project>
_ library can give any iterable object similar capabilities.
Convert any iterable object to a IterProxy
object:
.. code-block:: python
from iterproxy import IterProxy
# Suppose you have an iterable object
iterator = range(10)
# Convert it to a IterProxy object
proxy = IterProxy(iterator)
Access items from the IterProxy
object:
.. code-block:: python
proxy = IterProxy(range(10))
proxy.one() # it will return 0
proxy.many(3) # it will return [1, 2, 3]
proxy.skip(2).many(2) # it will skip [4, 5] and return [6, 7]
proxy.all() # it will return the rest [8, 9]
proxy.one_or_none() # it will return None
IterProxy.iter_chunks
can group items into chunks having K items, the last chunk may have less items than K:
.. code-block:: python
proxy = IterProxy(range(3))
list(proxy.iter_chunks(2)) # it will return [[0, 1], [2]]
Another example:
.. code-block:: python
proxy = IterProxy(range(10))
proxy.all() # it will return [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
Of course the IterProxy
itself is a iterator:
.. code-block:: python
for i in IterProxy(range(10)): # 0, 1, 2, ...
...
You can use custom filter function to filter the result. Other than the nesting style in built-in filter
function, it use chain pattern.
.. code-block:: python
def is_odd(x):
return x % 2 == 1
def gte_5(x):
return x >= 5
# with IterProxy, you can chain them
# it returns you [5, 7, 9]
for i in IterProxy(range(10)).filter(is_odd).filter(gte_5):
print(i)
# or put them together, by default, it is logic and
for i in IterProxy(range(10)).filter(is_odd, gte_5):
print(i)
# with the built-in filter, this is not that intuitive
for i in filter(gte_5, filter(is_odd, range(10))):
...
You can also use compound logic and_
, or_
, not_
:
.. code-block:: python
def is_odd(i):
return i % 2
def is_even(i):
return not (i % 2)
def lte_3(i):
return i <= 3
def gte_4(i):
return i >= 4
def lte_6(i):
return i <= 6
def gte_7(i):
return i >= 7
IterProxy(range(10)).filter(and_(gte_4, lte_6)).all() # [4, 5, 6]
IterProxy(range(10)).filter(or_(lte_3, gte_7)).all() # [0, 1, 2, 3, 7, 8, 9]
IterProxy(range(10)).filter(not_(is_odd)).all() # [0, 2, 4, 6, 8]
# of course you can nest and_, or_, not_
IterProxy(range(10)).filter(not_(and_(is_odd, or_(lte_3, gte_7)))).all() # [0, 2, 4, 5, 6, 8]
(Advanced) In order to enable type hint, you can do:
.. code-block:: python
from iterproxy import IterProxy
class Dog:
def bark(self):
pass
class DogIterProxy(IterProxy[Dog]): # subclass from IterProxy[${YourTypeHint}]
pass
many_dogs = [Dog(),]*10
proxy = DogIterProxy(many_dogs)
proxy.one_or_none().bark()
for dog in proxy.many(2):
dog.bark()
for dog in proxy.skip(1).many(2):
dog.bark()
for dog in proxy.all():
dog.bark()
filtered_proxy = DogIterProxy(many_dogs).filter(lambda dog: True)
filtered_proxy.one_or_none().bark()
for dog in filtered_proxy.many(2):
dog.bark()
for dog in filtered_proxy.skip(1).many(2):
dog.bark()
for dog in filtered_proxy.all():
dog.bark()
.. _install:
iterproxy
is released on PyPI, so all you need is:
.. code-block:: console
$ pip install iterproxy
To upgrade to latest version:
.. code-block:: console
$ pip install --upgrade iterproxy